Difference between revisions of "Fundamental theorems of calculus"

From MWiki
Jump to: navigation, search
m
(Fundamental theorems of calculus)
 
Line 1: Line 1:
'''First fundamental theorem of exact differential and integral calculus for line integrals:''' The function <math>F(z)={\uparrow}_{\gamma }{f(\zeta )dB\zeta }</math> ist mit <math>\gamma: [d, x[ \; \cap \; C \rightarrow A \subseteq \mathbb{K}, C \subseteq \mathbb{R}, f: A \rightarrow \mathbb{K}, d \in [a, b[ \; \cap \; C</math>, and choosing <math>\curvearrowright B \gamma(x) = \gamma(\curvearrowright D x)</math> is exactly <math>B</math>-differentiable, and for all <math>x \in [a, b[ \; \cap \; C</math> and <math>z = \gamma(x)</math>
+
'''First fundamental theorem of exact differential and integral calculus for line integrals:''' The function <math>F(z)={\uparrow}_{\gamma }{f(\zeta ){\downarrow}\zeta }</math> where <math>\gamma: [d, x[ \, \cap \, C \rightarrow A \subseteq {}^{(\omega)}\mathbb{K}, C \subseteq \mathbb{R}, f: A \rightarrow {}^{(\omega)}\mathbb{K}, d \in G = [a, b[ \, \cap \, C</math>, and choosing <math>{}^\curvearrowright \gamma(x) = \gamma({}^\curvearrowright x)</math> is exactly differentiable, and for all <math>x \in G</math> and <math>z = \gamma(x)</math>
  
<div style="text-align:center;"><math>F' \curvearrowright B(z) = f(z).</math></div>
+
<div style="text-align:center;"><math>F^{\prime}(z) = f(z).</math></div>
  
  
<table style="width:100%"><tr><td style="vertical-align: top; padding-top: 1em;">'''Proof:'''</td><td style="text-align: center; font-size: 84%;"><math>\begin{aligned}{\downarrow}B(F(z))&amp;={\uparrow}_{t\in [d,x] \; \cap \; C}{f(\gamma (t)){{{{\gamma }'}}_{\curvearrowright }}D(t){\downarrow}Dt}\;\,\;\;-{\uparrow}_{t\in [d,x[ \; \cap \; C}{f(\gamma (t)){{{{\gamma }'}}_{\curvearrowright }}D(t){\downarrow}Dt} \\ &amp;={\uparrow}_{x}{f(\gamma (t))\frac{\gamma (\curvearrowright Dt)-\gamma (t)}{\curvearrowright Dt-t}{\downarrow}Dt}=f(\gamma (x)){{{\gamma }'}_{\curvearrowright }}D(x){\downarrow}Dx=\,f(\gamma (x))(\curvearrowright B\gamma (x)-\gamma (x))=f(z){\downarrow}Bz.\square\end{aligned}</math></td></tr></table>
+
<table style="width:100%"><tr><td style="vertical-align: top; padding-top: 1em;">'''Proof:'''</td><td style="text-align: center; font-size: 84%;"><math>\begin{aligned}{\downarrow}F(z) &amp;={\uparrow}_{t\in [d,x] \cap C}{f(\gamma (t)){{\gamma }^{\prime}}(t){\downarrow}t}-{\uparrow}_{t\in [d,x[ \, \cap \, C}{f(\gamma (t)){{\gamma }^{\prime}}(t){\downarrow}t} &amp;={\uparrow}_{x}{f(\gamma (t))\tfrac{\gamma ({}^\curvearrowright t)-\gamma (t)}{{}^\curvearrowright t-t}{\downarrow}t} \\ &amp;=f(\gamma (x)){{\gamma}^{\prime}}(x){\downarrow}x=\;\;\;\;\;\;\;\;\;\;\;\;\;f(\gamma (x))({}^\curvearrowright\gamma (x)-\gamma (x)) &amp;=f(z){\downarrow}z.\square\end{aligned}</math></td></tr></table>
  
'''Second fundamental theorem of exact differential and integral calculus for line integrals:''' According to the conditions from above, it holds with <math>\gamma: [a, b[ \; \cap \; C \rightarrow \mathbb{K}</math> that
+
'''Second fundamental theorem of exact differential and integral calculus for line integrals:''' Conditions above imply with <math>\gamma: G \rightarrow {}^{(\omega)}\mathbb{K}</math> that
  
  
<div style="text-align:center;"><math> F(\gamma (b))-F(\gamma (a))={\uparrow}_{\gamma }{{{{{F}'}}_{\curvearrowright }}B(\zeta ){\downarrow}B\zeta }.</math></div>
+
<div style="text-align:center;"><math> F(\gamma (b))-F(\gamma (a))={\uparrow}_{\gamma }{{F^{\prime}}(\zeta ){\downarrow}\zeta }.</math></div>
  
  
<table style="width:100%"><tr><td style="vertical-align: top; padding-top: 0.4em;">'''Proof:'''</td><td style="text-align: center; font-size: 84%;"><math>\begin{aligned}F(\gamma (b))-F(\gamma (a))&amp;={+}_{t\in [a,b[ \; \cap \; C}{F(\curvearrowright B\,\gamma (t))}-F(\gamma (t))\;\,={+}_{t\in [a,b[ \; \cap \; C}{{{{{F}'}}_{\curvearrowright }}B(\gamma (t))(\curvearrowright B\,\gamma (t)-\gamma (t))} \\ &amp;={\uparrow}_{t\in [a,b[ \; \cap \; C}{{{{{F}'}}_{\curvearrowright }}B(\gamma (t)){{{{\gamma }'}}_{\curvearrowright }}D(t){\downarrow}Dt}={\uparrow}_{\gamma }{{{{{F}'}}_{\curvearrowright }}B(\zeta ){\downarrow}B\zeta }.\square\end{aligned}</math></td></tr></table>
+
<table style="width:100%"><tr><td style="vertical-align: top; padding-top: 0.4em;">'''Proof:'''</td><td style="text-align: center; font-size: 84%;"><math>\begin{aligned}F(\gamma (b))-F(\gamma (a)) &amp;={+}_{t\in G}{F({}^\curvearrowright\,\gamma (t))}-F(\gamma (t)) &amp;={+}_{t\in G}{{{F}^{\prime}}(\gamma (t))({}^\curvearrowright\,\gamma (t)-\gamma (t))} \\ &amp;={\uparrow}_{t\in G}{{F^{\prime}}(\gamma (t)){{\gamma }^{\prime}}(t){\downarrow}t} &amp;={\uparrow}_{\gamma }{{F_{{}^\curvearrowright }^{\prime}}(\zeta ){\downarrow}\zeta }.\square\end{aligned}</math></td></tr></table>
  
 
== See also ==
 
== See also ==

Latest revision as of 16:55, 29 September 2023

First fundamental theorem of exact differential and integral calculus for line integrals: The function [math]\displaystyle{ F(z)={\uparrow}_{\gamma }{f(\zeta ){\downarrow}\zeta } }[/math] where [math]\displaystyle{ \gamma: [d, x[ \, \cap \, C \rightarrow A \subseteq {}^{(\omega)}\mathbb{K}, C \subseteq \mathbb{R}, f: A \rightarrow {}^{(\omega)}\mathbb{K}, d \in G = [a, b[ \, \cap \, C }[/math], and choosing [math]\displaystyle{ {}^\curvearrowright \gamma(x) = \gamma({}^\curvearrowright x) }[/math] is exactly differentiable, and for all [math]\displaystyle{ x \in G }[/math] and [math]\displaystyle{ z = \gamma(x) }[/math]

[math]\displaystyle{ F^{\prime}(z) = f(z). }[/math]


Proof:[math]\displaystyle{ \begin{aligned}{\downarrow}F(z) &={\uparrow}_{t\in [d,x] \cap C}{f(\gamma (t)){{\gamma }^{\prime}}(t){\downarrow}t}-{\uparrow}_{t\in [d,x[ \, \cap \, C}{f(\gamma (t)){{\gamma }^{\prime}}(t){\downarrow}t} &={\uparrow}_{x}{f(\gamma (t))\tfrac{\gamma ({}^\curvearrowright t)-\gamma (t)}{{}^\curvearrowright t-t}{\downarrow}t} \\ &=f(\gamma (x)){{\gamma}^{\prime}}(x){\downarrow}x=\;\;\;\;\;\;\;\;\;\;\;\;\;f(\gamma (x))({}^\curvearrowright\gamma (x)-\gamma (x)) &=f(z){\downarrow}z.\square\end{aligned} }[/math]

Second fundamental theorem of exact differential and integral calculus for line integrals: Conditions above imply with [math]\displaystyle{ \gamma: G \rightarrow {}^{(\omega)}\mathbb{K} }[/math] that


[math]\displaystyle{ F(\gamma (b))-F(\gamma (a))={\uparrow}_{\gamma }{{F^{\prime}}(\zeta ){\downarrow}\zeta }. }[/math]


Proof:[math]\displaystyle{ \begin{aligned}F(\gamma (b))-F(\gamma (a)) &={+}_{t\in G}{F({}^\curvearrowright\,\gamma (t))}-F(\gamma (t)) &={+}_{t\in G}{{{F}^{\prime}}(\gamma (t))({}^\curvearrowright\,\gamma (t)-\gamma (t))} \\ &={\uparrow}_{t\in G}{{F^{\prime}}(\gamma (t)){{\gamma }^{\prime}}(t){\downarrow}t} &={\uparrow}_{\gamma }{{F_{{}^\curvearrowright }^{\prime}}(\zeta ){\downarrow}\zeta }.\square\end{aligned} }[/math]

See also